Integrand size = 25, antiderivative size = 218 \[ \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}} \, dx=\frac {2 a b \left (15 a^2+62 b^2\right ) (e \cos (c+d x))^{3/2}}{15 d e^3}-\frac {2 \left (5 a^4+60 a^2 b^2+12 b^4\right ) \sqrt {e \cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{5 d e^2 \sqrt {\cos (c+d x)}}+\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e^3}+\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e^3}+\frac {2 (b+a \sin (c+d x)) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}} \]
2/15*a*b*(15*a^2+62*b^2)*(e*cos(d*x+c))^(3/2)/d/e^3+2/5*b*(5*a^2+6*b^2)*(e *cos(d*x+c))^(3/2)*(a+b*sin(d*x+c))/d/e^3+2*a*b*(e*cos(d*x+c))^(3/2)*(a+b* sin(d*x+c))^2/d/e^3+2*(b+a*sin(d*x+c))*(a+b*sin(d*x+c))^3/d/e/(e*cos(d*x+c ))^(1/2)-2/5*(5*a^4+60*a^2*b^2+12*b^4)*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/ 2*d*x+1/2*c)*EllipticE(sin(1/2*d*x+1/2*c),2^(1/2))*(e*cos(d*x+c))^(1/2)/d/ e^2/cos(d*x+c)^(1/2)
Time = 1.26 (sec) , antiderivative size = 135, normalized size of antiderivative = 0.62 \[ \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}} \, dx=\frac {-6 \left (5 a^4+60 a^2 b^2+12 b^4\right ) \sqrt {\cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )+\frac {1}{2} \left (240 a^3 b+280 a b^3+40 a b^3 \cos (2 (c+d x))+\left (60 a^4+360 a^2 b^2+63 b^4\right ) \sin (c+d x)+3 b^4 \sin (3 (c+d x))\right )}{15 d e \sqrt {e \cos (c+d x)}} \]
(-6*(5*a^4 + 60*a^2*b^2 + 12*b^4)*Sqrt[Cos[c + d*x]]*EllipticE[(c + d*x)/2 , 2] + (240*a^3*b + 280*a*b^3 + 40*a*b^3*Cos[2*(c + d*x)] + (60*a^4 + 360* a^2*b^2 + 63*b^4)*Sin[c + d*x] + 3*b^4*Sin[3*(c + d*x)])/2)/(15*d*e*Sqrt[e *Cos[c + d*x]])
Time = 1.14 (sec) , antiderivative size = 224, normalized size of antiderivative = 1.03, number of steps used = 15, number of rules used = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {3042, 3170, 27, 3042, 3341, 27, 3042, 3341, 27, 3042, 3148, 3042, 3121, 3042, 3119}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}} \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}}dx\) |
| \(\Big \downarrow \) 3170 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {2 \int \frac {1}{2} \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2 \left (a^2+7 b \sin (c+d x) a+6 b^2\right )dx}{e^2}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\int \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2 \left (a^2+7 b \sin (c+d x) a+6 b^2\right )dx}{e^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\int \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2 \left (a^2+7 b \sin (c+d x) a+6 b^2\right )dx}{e^2}\) |
| \(\Big \downarrow \) 3341 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\frac {2}{7} \int \frac {7}{2} \sqrt {e \cos (c+d x)} (a+b \sin (c+d x)) \left (a \left (a^2+10 b^2\right )+b \left (5 a^2+6 b^2\right ) \sin (c+d x)\right )dx-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\int \sqrt {e \cos (c+d x)} (a+b \sin (c+d x)) \left (a \left (a^2+10 b^2\right )+b \left (5 a^2+6 b^2\right ) \sin (c+d x)\right )dx-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\int \sqrt {e \cos (c+d x)} (a+b \sin (c+d x)) \left (a \left (a^2+10 b^2\right )+b \left (5 a^2+6 b^2\right ) \sin (c+d x)\right )dx-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 3341 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\frac {2}{5} \int \frac {1}{2} \sqrt {e \cos (c+d x)} \left (5 a^4+60 b^2 a^2+b \left (15 a^2+62 b^2\right ) \sin (c+d x) a+12 b^4\right )dx-\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e}-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\frac {1}{5} \int \sqrt {e \cos (c+d x)} \left (5 a^4+60 b^2 a^2+b \left (15 a^2+62 b^2\right ) \sin (c+d x) a+12 b^4\right )dx-\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e}-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\frac {1}{5} \int \sqrt {e \cos (c+d x)} \left (5 a^4+60 b^2 a^2+b \left (15 a^2+62 b^2\right ) \sin (c+d x) a+12 b^4\right )dx-\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e}-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 3148 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\frac {1}{5} \left (\left (5 a^4+60 a^2 b^2+12 b^4\right ) \int \sqrt {e \cos (c+d x)}dx-\frac {2 a b \left (15 a^2+62 b^2\right ) (e \cos (c+d x))^{3/2}}{3 d e}\right )-\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e}-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\frac {1}{5} \left (\left (5 a^4+60 a^2 b^2+12 b^4\right ) \int \sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )}dx-\frac {2 a b \left (15 a^2+62 b^2\right ) (e \cos (c+d x))^{3/2}}{3 d e}\right )-\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e}-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 3121 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\frac {1}{5} \left (\frac {\left (5 a^4+60 a^2 b^2+12 b^4\right ) \sqrt {e \cos (c+d x)} \int \sqrt {\cos (c+d x)}dx}{\sqrt {\cos (c+d x)}}-\frac {2 a b \left (15 a^2+62 b^2\right ) (e \cos (c+d x))^{3/2}}{3 d e}\right )-\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e}-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {\frac {1}{5} \left (\frac {\left (5 a^4+60 a^2 b^2+12 b^4\right ) \sqrt {e \cos (c+d x)} \int \sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}dx}{\sqrt {\cos (c+d x)}}-\frac {2 a b \left (15 a^2+62 b^2\right ) (e \cos (c+d x))^{3/2}}{3 d e}\right )-\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e}-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
| \(\Big \downarrow \) 3119 |
| \(\displaystyle \frac {2 (a \sin (c+d x)+b) (a+b \sin (c+d x))^3}{d e \sqrt {e \cos (c+d x)}}-\frac {-\frac {2 b \left (5 a^2+6 b^2\right ) (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))}{5 d e}+\frac {1}{5} \left (\frac {2 \left (5 a^4+60 a^2 b^2+12 b^4\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{d \sqrt {\cos (c+d x)}}-\frac {2 a b \left (15 a^2+62 b^2\right ) (e \cos (c+d x))^{3/2}}{3 d e}\right )-\frac {2 a b (e \cos (c+d x))^{3/2} (a+b \sin (c+d x))^2}{d e}}{e^2}\) |
(2*(b + a*Sin[c + d*x])*(a + b*Sin[c + d*x])^3)/(d*e*Sqrt[e*Cos[c + d*x]]) - (((-2*a*b*(15*a^2 + 62*b^2)*(e*Cos[c + d*x])^(3/2))/(3*d*e) + (2*(5*a^4 + 60*a^2*b^2 + 12*b^4)*Sqrt[e*Cos[c + d*x]]*EllipticE[(c + d*x)/2, 2])/(d *Sqrt[Cos[c + d*x]]))/5 - (2*b*(5*a^2 + 6*b^2)*(e*Cos[c + d*x])^(3/2)*(a + b*Sin[c + d*x]))/(5*d*e) - (2*a*b*(e*Cos[c + d*x])^(3/2)*(a + b*Sin[c + d *x])^2)/(d*e))/e^2
3.6.69.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* (c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
Int[((b_)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*Sin[c + d*x]) ^n/Sin[c + d*x]^n Int[Sin[c + d*x]^n, x], x] /; FreeQ[{b, c, d}, x] && Lt Q[-1, n, 1] && IntegerQ[2*n]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)]), x_Symbol] :> Simp[(-b)*((g*Cos[e + f*x])^(p + 1)/(f*g*(p + 1))), x] + Simp[a Int[(g*Cos[e + f*x])^p, x], x] /; FreeQ[{a, b, e, f, g, p}, x] && (IntegerQ[2*p] || NeQ[a^2 - b^2, 0])
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[(-(g*Cos[e + f*x])^(p + 1))*(a + b*Sin[e + f*x ])^(m - 1)*((b + a*Sin[e + f*x])/(f*g*(p + 1))), x] + Simp[1/(g^2*(p + 1)) Int[(g*Cos[e + f*x])^(p + 2)*(a + b*Sin[e + f*x])^(m - 2)*(b^2*(m - 1) + a^2*(p + 2) + a*b*(m + p + 1)*Sin[e + f*x]), x], x] /; FreeQ[{a, b, e, f, g }, x] && NeQ[a^2 - b^2, 0] && GtQ[m, 1] && LtQ[p, -1] && (IntegersQ[2*m, 2* p] || IntegerQ[m])
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-d)* (g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^m/(f*g*(m + p + 1))), x] + S imp[1/(m + p + 1) Int[(g*Cos[e + f*x])^p*(a + b*Sin[e + f*x])^(m - 1)*Sim p[a*c*(m + p + 1) + b*d*m + (a*d*m + b*c*(m + p + 1))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && NeQ[a^2 - b^2, 0] && GtQ[m, 0] && !LtQ[p, -1] && IntegerQ[2*m] && !(EqQ[m, 1] && NeQ[c^2 - d^2, 0] && S implerQ[c + d*x, a + b*x])
Time = 8.51 (sec) , antiderivative size = 378, normalized size of antiderivative = 1.73
| method | result | size |
| default | \(\frac {\frac {16 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{4}}{5}-\frac {16 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{4}}{5}+\frac {32 \left (\sin ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{3}}{3}+4 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{4}+24 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2} b^{2}+\frac {24 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{4}}{5}-2 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) a^{4}-24 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) a^{2} b^{2}-\frac {24 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) b^{4}}{5}-\frac {32 \left (\sin ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{3}}{3}+8 \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} b +\frac {32 \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) a \,b^{3}}{3}}{e \sqrt {-2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +e}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) d}\) | \(378\) |
| parts | \(-\frac {2 a^{4} \left (-2 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e}\, \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, \sqrt {-2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )\right )}{e \sqrt {-e \left (2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right )}\, d}+\frac {8 b^{4} \sqrt {-2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e}\, \left (2 \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )-2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+3 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )-3 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )\right )}{5 e \sqrt {-e \left (2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right )}\, d}+\frac {8 a \,b^{3} \left (\frac {\left (e \cos \left (d x +c \right )\right )^{\frac {3}{2}}}{3}+\frac {e^{2}}{\sqrt {e \cos \left (d x +c \right )}}\right )}{d \,e^{3}}-\frac {24 a^{2} b^{2} \left (-\cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e}\, \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, \sqrt {-2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )\right )}{e \sqrt {-e \left (2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right )}\, d}+\frac {8 a^{3} b}{\sqrt {e \cos \left (d x +c \right )}\, e d}\) | \(681\) |
2/15/e/(-2*sin(1/2*d*x+1/2*c)^2*e+e)^(1/2)/sin(1/2*d*x+1/2*c)*(24*cos(1/2* d*x+1/2*c)*sin(1/2*d*x+1/2*c)^6*b^4-24*cos(1/2*d*x+1/2*c)*sin(1/2*d*x+1/2* c)^4*b^4+80*sin(1/2*d*x+1/2*c)^5*a*b^3+30*cos(1/2*d*x+1/2*c)*sin(1/2*d*x+1 /2*c)^2*a^4+180*cos(1/2*d*x+1/2*c)*sin(1/2*d*x+1/2*c)^2*a^2*b^2+36*cos(1/2 *d*x+1/2*c)*sin(1/2*d*x+1/2*c)^2*b^4-15*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*si n(1/2*d*x+1/2*c)^2-1)^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),2^(1/2))*a^4-180* (sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*sin(1/2*d*x+1/2*c)^2-1)^(1/2)*EllipticE(co s(1/2*d*x+1/2*c),2^(1/2))*a^2*b^2-36*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*sin(1 /2*d*x+1/2*c)^2-1)^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),2^(1/2))*b^4-80*sin( 1/2*d*x+1/2*c)^3*a*b^3+60*sin(1/2*d*x+1/2*c)*a^3*b+80*sin(1/2*d*x+1/2*c)*a *b^3)/d
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.12 (sec) , antiderivative size = 203, normalized size of antiderivative = 0.93 \[ \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}} \, dx=-\frac {3 \, \sqrt {2} {\left (5 i \, a^{4} + 60 i \, a^{2} b^{2} + 12 i \, b^{4}\right )} \sqrt {e} \cos \left (d x + c\right ) {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right )\right ) + 3 \, \sqrt {2} {\left (-5 i \, a^{4} - 60 i \, a^{2} b^{2} - 12 i \, b^{4}\right )} \sqrt {e} \cos \left (d x + c\right ) {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right )\right ) - 2 \, {\left (20 \, a b^{3} \cos \left (d x + c\right )^{2} + 60 \, a^{3} b + 60 \, a b^{3} + 3 \, {\left (b^{4} \cos \left (d x + c\right )^{2} + 5 \, a^{4} + 30 \, a^{2} b^{2} + 5 \, b^{4}\right )} \sin \left (d x + c\right )\right )} \sqrt {e \cos \left (d x + c\right )}}{15 \, d e^{2} \cos \left (d x + c\right )} \]
-1/15*(3*sqrt(2)*(5*I*a^4 + 60*I*a^2*b^2 + 12*I*b^4)*sqrt(e)*cos(d*x + c)* weierstrassZeta(-4, 0, weierstrassPInverse(-4, 0, cos(d*x + c) + I*sin(d*x + c))) + 3*sqrt(2)*(-5*I*a^4 - 60*I*a^2*b^2 - 12*I*b^4)*sqrt(e)*cos(d*x + c)*weierstrassZeta(-4, 0, weierstrassPInverse(-4, 0, cos(d*x + c) - I*sin (d*x + c))) - 2*(20*a*b^3*cos(d*x + c)^2 + 60*a^3*b + 60*a*b^3 + 3*(b^4*co s(d*x + c)^2 + 5*a^4 + 30*a^2*b^2 + 5*b^4)*sin(d*x + c))*sqrt(e*cos(d*x + c)))/(d*e^2*cos(d*x + c))
Timed out. \[ \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}} \, dx=\text {Timed out} \]
\[ \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}} \, dx=\int { \frac {{\left (b \sin \left (d x + c\right ) + a\right )}^{4}}{\left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}}} \,d x } \]
\[ \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}} \, dx=\int { \frac {{\left (b \sin \left (d x + c\right ) + a\right )}^{4}}{\left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}}} \,d x } \]
Timed out. \[ \int \frac {(a+b \sin (c+d x))^4}{(e \cos (c+d x))^{3/2}} \, dx=\int \frac {{\left (a+b\,\sin \left (c+d\,x\right )\right )}^4}{{\left (e\,\cos \left (c+d\,x\right )\right )}^{3/2}} \,d x \]